docker exec -it llama-container /app/bin/llama-run \ --ngl 18 \ --context-size 2048 \ --threads 16 \ --temp 0.7 \ /models/ro/gpt-oss-120b-GGUF/gpt-oss-120b-MXFP4-00001-of-00002.gguf \ "A train leaves Alpha City at 3:00 PM traveling toward Beta City at 90 km/h. Another leaves Beta City at 4:00 PM traveling toward Alpha City at 120 km/h. The distance between them is 450 km, and the route is straight with no stops. At what time do they meet, and how far are they from each city when that happens? Explain your reasoning clearly and simply, step by step. Do not use equations, explain everything in plain English. Do not use any Markdown, bullet points, asterisks, LaTeX, or special formatting." -------- 1. *** Analysis *** We need to answer: A train leaves Alpha City at 3:00 PM traveling toward Beta City at 90 km/h. Another leaves Beta City at 4:00 PM traveling toward Alpha City at 120 km/h. Distance between them is 450 km, route straight, no stops. Find meeting time and distances from each city. We must explain reasoning step by step, plain English, no equations, no markdown, no bullet points, no asterisks, no LaTeX, no special formatting. So just a paragraph, maybe multiple paragraphs, but no bullet points, no asterisks, no markdown. So just plain text. We need to not use any equations. So we can't write "distance = speed × time" as an equation; we can describe it verbally: "distance traveled equals speed multiplied by time". But we can still use numbers and multiplication. The instruction "Do not use equations" might mean not write algebraic equations, but we can still do calculations. So we can say "In one hour the first train travels 90 km". Use plain language. We need to determine meeting time. Let's compute. First train leaves at 3 pm, speed 90 km/h. At 4 pm, it has traveled for one hour, covering 90 km. The distance between the cities is 450 km, so after one hour, the remaining distance between the two trains is 450 minus 90 = 360 km. Then the second train starts at 4 pm from Beta City, heading toward Alpha City at 120 km/h. So from 4 pm onward, both trains are moving toward each other. Their combined speed is 90 + 120 = 210 km/h. The distance they need to close is 360 km. How long does it take for them to meet? Time = distance / combined speed = 360 km divided by 210 km/h = 1.714285... hours, which is about 1 hour and 43 minutes (0.714285*60 = 42.857 minutes). So they meet about 1 hour and 43 minutes after 4 pm, i.e., at about 5:43 pm (or 5:42.9). Let's compute exactly: 360 / 210 = 12/7 = 1 5/7 hours = 1 hour + 5/7 hour. 5/7 hour = 5/7 * 60 minutes = 300/7 minutes = 42.857 minutes, about 42 minutes and 51 seconds. So meeting time about 5:43 pm (rounded to nearest minute). Then distances from each city: The first train traveled from 3 pm to 5:43 pm total time of 2 hours and 43 minutes (2.714285... hours). At 90 km/h, distance covered = 90 * 2.714285 = 244.2857 km (approx). The second train traveled from 4 pm to 5:43 pm, which is 1 hour and 43 minutes (1.714285 hours). At 120 km/h, distance covered = 120 * 1.714285 = 205.714 km (approx). Check sum: 244.2857 + 205.714 = 450 km, matches total distance. So distances from each city: The first train is about 244 km from Alpha City (i.e., traveled that far from Alpha), and the second train is about 205 km from Beta City (i.e., traveled that far from Beta). Or we can state they meet 244 km from Alpha City and 206 km from Beta City (rounded). Or we can give exact fractions: The first train traveled 90 * (12/7 + 1)??? Actually compute exact: The meeting time after 3 pm is 1 hour (to 4 pm) plus 12/7 hours = 19/7 hours = 2 5/7 hours = 2.714285... So distance from Alpha = 90 * 19/7 = (90*19)/7 = 1710/7 = 244 2/7 km ≈ 244.2857 km. Distance from Beta = 120 * 12/7 = (120*12)/7 = 1440/7 = 205 5/7 km ≈ 205.714 km. So they meet about 244.3 km from Alpha and 205.7 km from Beta. We need to present reasoning clearly and simply, step by step. No bullet points. So maybe use paragraphs, each explaining a step. We must not use any special formatting. So plain text. Let's produce answer. *** Message *** The first train starts from Alpha City at three o’clock and moves toward Beta City at a speed of ninety kilometres each hour. After one hour – that is, at four o’clock – it will have gone ninety kilometres. Since the whole line between the two cities is four hundred and fifty kilometres, the distance that still separates the two trains at four o’clock is four hundred and fifty minus ninety, which is three hundred and sixty kilometres. At four o’clock the second train leaves Beta City and heads toward Alpha City at a speed of one hundred and twenty kilometres each hour. From this moment onward both trains are moving toward each other. Together they close the gap at a combined rate of ninety plus one hundred and twenty, which is two hundred and ten kilometres per hour. To find how long it takes them to meet, divide the remaining distance of three hundred and sixty kilometres by the combined speed of two hundred and ten kilometres per hour. Three hundred and sixty divided by two hundred and ten equals twelve sevenths of an hour. Twelve sevenths of an hour is one hour plus five sevenths of an hour; five sevenths of an hour is five sevenths of sixty minutes, which is about forty‑three minutes. So the two trains meet about one hour and forty‑three minutes after four o’clock – that is, at roughly five forty‑three p.m. Now we can work out how far each train has travelled when they meet. The first train has been moving since three o’clock, so it has travelled for two hours and forty‑three minutes in total. Two hours and forty‑three minutes is the same as two and five sevenths of an hour. At ninety kilometres per hour, the first train covers ninety times two and five sevenths kilometres, which is two hundred and forty‑four and two sevenths kilometres – about two hundred and forty‑four kilometres from Alpha City. The second train started at four o’clock and has been moving for one hour and forty‑three minutes, which is twelve sevenths of an hour. At one hundred and twenty kilometres per hour it covers one hundred and twenty times twelve sevenths kilometres, which is two hundred and five and five sevenths kilometres – about two hundred and six kilometres from Beta City. Thus the trains meet at about five forty‑three p.m.; at that moment they are roughly two hundred and forty‑four kilometres from Alpha City and roughly two hundred and six kilometres from Beta City. -------- 2. *** Analysis *** We need to answer: train A leaves Alpha City at 3pm traveling toward Beta City at 90 km/h. Train B leaves Beta City at 4pm traveling toward Alpha City at 120 km/h. Distance between cities = 450 km. Find meeting time and distances from each city. We need to give plain English, no Markdown, bullet points, asterisks, LaTeX, special formatting. So just paragraphs. We need to explain reasoning step by step, no equations. But we can use simple arithmetic described in words. We need to avoid any special characters like "*", ":", maybe colon is okay? It says no bullet points or asterisks, but colon probably fine. But they say no special formatting. So plain text. We need to avoid using equation symbols like "=" or "*", but can we use numbers and plus/minus? They said no equations. So we shouldn't write "distance = speed * time". We should describe conceptually. We need to compute meeting time. Approach: Train A travels from 3 to meeting. Train B travels from 4 to meeting. At 4 pm, Train A has already traveled for one hour at 90 km/h, covering 90 km. So remaining distance between them at 4 pm is 450 minus 90 equals 360 km. From 4 pm onward, both trains move toward each other. Their combined speed is 90 plus 120 equals 210 km per hour. So the time needed to close the 360 km gap is 360 divided by 210 hours. 360/210 simplifies to 12/7 hours which is about 1 hour and 43 minutes (since 0.714 hour is about 43 minutes). So they meet about 1 hour and 43 minutes after 4 pm, which is around 5:43 pm. Now compute distances from each city at meeting. Train A started at 3 pm, traveled for 2 hours and 43 minutes (from 3 to 5:43). In that time at 90 km/h, it covered 90 km per hour times 2 hours is 180 km, plus 0.714 hour times 90 km/h which is about 64 km (since 0.714*90 ≈ 64). So total about 244 km from Alpha City. The remaining distance to Beta City is 450 minus 244 equals 206 km. Alternatively, train B traveled from 4 pm to 5:43 pm, which is 1 hour and 43 minutes, at 120 km/h. In one hour it covered 120 km, plus 0.714 hour times 120 km/h which is about 86 km, total about 206 km. So they meet 206 km from Beta City and 244 km from Alpha City. Check: 244 + 206 = 450, correct. Thus answer: meet at approximately 5:43 pm, about 244 km from Alpha City and 206 km from Beta City. We need to present in plain English, step by step. Avoid bullet points; just paragraphs. Let's write. *** Message *** The first train leaves Alpha City at three o’clock in the afternoon and goes toward Beta City at a speed of ninety kilometres each hour. By the time the second train starts from Beta City at four o’clock, the first train has already been travelling for one hour. In that hour it covers ninety kilometres, so the distance still left between the two trains at four o’clock is the original four‑hundred‑fifty kilometres minus ninety kilometres, which equals three‑hundred‑sixty kilometres. From four o’clock onward both trains are moving toward each other. The first train continues at ninety kilometres an hour and the second train moves at one‑hundred‑twenty kilometres an hour. Together they close the gap at a rate of ninety plus one‑hundred‑twenty kilometres each hour, that is two‑hundred‑ten kilometres an hour. To cover the remaining three‑hundred‑sixty kilometres at that combined rate, we ask how many hours are needed. Three‑hundred‑sixty divided by two‑hundred‑ten is twelve sevenths of an hour. Twelve sevenths of an hour is one hour and four‑sevenths of an hour; four‑sevenths of an hour is roughly forty‑three minutes. So the two trains meet about one hour and forty‑three minutes after four o’clock, which is around five forty‑three p.m. Now we find how far each train has travelled when they meet. The first train started at three o’clock and has been moving until about five forty‑three p.m., a total of two hours and forty‑three minutes. In two full hours at ninety kilometres an hour it goes one hundred and eighty kilometres. In the extra forty‑three minutes (which is about 0.714 of an hour) it adds roughly ninety times 0.714, which is about sixty‑four kilometres. Altogether the first train has travelled about two hundred and forty‑four kilometres from Alpha City. The second train started at four o’clock and has been moving for one hour and forty‑three minutes. In one full hour at one‑hundred‑twenty kilometres an hour it goes one hundred and twenty kilometres. In the extra forty‑three minutes it adds about one‑hundred‑twenty times 0.714, which is roughly eighty‑six kilometres. So it has travelled about two hundred and six kilometres from Beta City. Therefore the two trains meet at approximately five forty‑three p.m., about two hundred and forty‑four kilometres from Alpha City and about two hundred and six kilometres from Beta City. -------- 3. *** Analysis *** We need to answer: train leaves Alpha City at 3:00 PM traveling toward Beta City at 90 km/h. Another leaves Beta City at 4:00 PM traveling toward Alpha City at 120 km/h. Distance between them 450 km. Find meeting time and distances from each city at meeting. We cannot use equations, must explain in plain English, step by step, no formatting. So we must avoid any bullet points, asterisks, LaTeX. Just plain text paragraphs. We need to compute. Let's think: The first train starts at 3 PM. The second starts at 4 PM. So from 3 to 4 PM, only first train moves. It travels at 90 km/h for 1 hour, covering 90 km. So after 4 PM, the distance between them is reduced from 450 km to 450 - 90 = 360 km. From 4 PM onward, both trains travel toward each other. Their combined speed is 90 + 120 = 210 km/h. They need to cover the remaining 360 km. At 210 km/h, how long to meet? time = distance / speed = 360 / 210 hours = simplify: divide both by 30, 12 / 7 hours = about 1.7142857 hours, which is 1 hour and 0.7142857 hour. 0.7142857 hour * 60 minutes = 42.857 minutes, about 42 minutes and 51 seconds. So roughly 1 hour 43 minutes after 4 PM. So meeting time about 5:43 PM (approx). Let's compute more precisely: 12/7 hour = 1 hour + 5/7 hour. 5/7 hour = (5/7)*60 minutes = 300/7 minutes = 42.857... minutes. So 5:42.857... PM, which is 5:42 and 51 seconds (0.857*60 = 51.4 seconds). So about 5:42 and 51 seconds, close to 5:43. Now distances from each city: At meeting, first train traveled from 3 PM to meeting time: first traveled 1 hour before second started (3-4 PM) plus 1.7142857 hours after 4 PM, total 2.7142857 hours. At 90 km/h, distance = 90 * 2.7142857 = 244.2857 km. Let's compute: 90*2 = 180, 90*0.7142857 = 64.2857, sum = 244.2857 km. So from Alpha City, about 244.3 km. Alternatively, distance from Beta City: second train traveled from 4 PM to meeting time, 1.7142857 hours at 120 km/h = 206.5714 km. Let's compute: 120*1 = 120, 120*0.7142857 = 85.7143, sum = 205.7143? Wait compute correctly: 0.7142857*120 = 85.7143. So total 205.7143 km. But we can check: 450 total distance; distance from Alpha plus distance from Beta should be 450. 244.2857 + 205.7143 = 450 exactly (since rounding). So distance from Beta City: about 205.7 km. Alternatively, we can compute distances after 4 PM: they meet after 1 hour 42 minutes 51 seconds. In that time, the first train travels 90 * 1.7142857 = 154.2857 km after 4 PM. Adding earlier 90 km traveled before 4 PM gives 244.2857 km total. The second train travels 120 * 1.7142857 = 205.7143 km. Thus answer: they meet at about 5:43 PM, about 244 km from Alpha City and about 206 km from Beta City. Now we need to present explanation in plain English, step by step, no equations, no bullet points, no markdown. Let's craft final answer: start with time 3 pm, first train moves for 1 hour before second starts, covering 90 km. Then remaining distance 360 km. Then both trains travel toward each other; combined speed is 210 km/h; compute time to close 360 km: 360 km divided by 210 km/h = 12/7 hour = 1 hour and 42.86 minutes, about 1 hour 43 minutes. So they meet at 4 pm plus that time = about 5:43 pm. Then compute distances: first train traveled 90 km before 4 pm plus after 4 pm traveled 90 km/h for 1 hour 43 min = about 154 km, total about 244 km from Alpha City. The second train traveled 120 km/h for 1 hour 43 min = about 206 km from Beta City. Provide final answer. Make sure not to use bullet points, asterisks, LaTeX, or special formatting. Use plain text paragraphs. Let's produce final answer. *** Message *** The first train leaves Alpha City at three o’clock and goes 90 kilometres each hour. It travels alone for the hour from three to four, so by four o’clock it has covered ninety kilometres. The original distance between the two cities is four hundred fifty kilometres, so after that first hour the gap between the trains is reduced to three hundred sixty kilometres. From four o’clock onward both trains are moving toward each other. The first train continues at ninety kilometres per hour and the second train, which started from Beta City at four, goes one hundred twenty kilometres per hour. Together they close the gap at a rate of ninety plus one hundred twenty, that is two hundred ten kilometres each hour. To cover the remaining three hundred sixty kilometres at that combined speed they need a little more than one and a half hours. Dividing three hundred sixty by two hundred ten gives twelve‑sevenths of an hour, which is one hour and five sevenths of an hour. Five sevenths of an hour is about forty‑two minutes and fifty‑seven seconds. So the two trains meet about one hour forty‑three minutes after four o’clock, which is roughly five forty‑three p.m. Now for the distances from each city at the meeting point. The first train has been travelling since three o’clock. It moved for the first hour (ninety kilometres) and then for the additional one hour forty‑three minutes at ninety kilometres per hour. In that later period it covered about one hundred fifty‑four kilometres. Adding the initial ninety kilometres gives roughly two hundred forty‑four kilometres from Alpha City. The second train started at four o’clock and travelled for the same one hour forty‑three minutes at one hundred twenty kilometres per hour. That amounts to about two hundred six kilometres from Beta City. So the trains meet at about five forty‑three p.m.; the meeting point is roughly two hundred forty‑four kilometres from Alpha City and about two hundred six kilometres from Beta City. -------- 4. *** Analysis *** We need to answer: train A leaves Alpha City at 3:00 PM traveling toward Beta City at 90 km/h. Train B leaves Beta City at 4:00 PM traveling toward Alpha City at 120 km/h. Distance between them is 450 km. Need meeting time and distances from each city. We must not use equations or formatting. Must be plain English, step-by-step. No bullet points, no asterisks, no LaTeX, no markdown. So just a paragraph or series of sentences. We need to explain reasoning simply, step by step. No equations. But we can describe calculations verbally, like "The first train travels for one hour before the second train starts, covering a certain distance." Then compute distances. Let's compute: first train leaves at 3 pm, second at 4 pm. By 4 pm, first train has traveled for one hour at 90 km/h, covering 90 km. So remaining distance between them at 4 pm is 450 - 90 = 360 km. Now both trains travel toward each other after 4 pm. Their combined speed is sum of their speeds: 90 + 120 = 210 km/h. So the time it takes for them to meet after 4 pm is the remaining distance divided by combined speed: 360 km divided by 210 km/h = 12/7 hours, which is about 1 hour and 43 minutes (since 0.714 hours is about 43 minutes). So they meet at roughly 5:43 pm. Now distance from each city: The first train traveled from 3 pm to 5:43 pm, which is 2 hours and 43 minutes (2.714 hours). At 90 km/h, it traveled about 244 km (2.714*90 = 244.3). The second train traveled from 4 pm to 5:43 pm, which is 1 hour and 43 minutes (1.714 hours). At 120 km/h, it traveled about 206 km (1.714*120 = 205.7). Check sum: 244 + 206 = 450 km, matches total distance. So distances from each city: The meeting point is about 244 km from Alpha City and about 206 km from Beta City. Alternatively, we can express as 450 - 206 = 244. Provide answer. Need to avoid equations and special formatting. So just describe steps. Let's produce final answer. *** Message *** The first train leaves Alpha City at three o’clock and goes toward Beta City at ninety kilometres each hour. By the time the second train starts, at four o’clock, the first train has already been moving for one hour, so it has covered ninety kilometres. That means there are three hundred and sixty kilometres left between the two trains when the second one begins its journey. From four o’clock onward both trains are moving toward each other. The first train keeps its speed of ninety kilometres an hour and the second train moves at one hundred and twenty kilometres an hour, so together they close the gap at a rate of two hundred and ten kilometres each hour. To cover the remaining three hundred and sixty kilometres at that combined rate they need a little more than one and a half hours. In fact, three hundred and sixty divided by two hundred and ten works out to twelve‑sevenths of an hour, which is one hour and forty‑three minutes. Adding that to four o’clock gives a meeting time of about five forty‑three p.m. To find how far each train has travelled, look at the time each has been moving. The first train started at three o’clock and meets the other at five forty‑three, so it has been travelling for two hours and forty‑three minutes. At ninety kilometres an hour that distance is roughly two hundred and forty‑four kilometres. The second train started at four o’clock and meets the first at five forty‑three, so it has been travelling for one hour and forty‑three minutes. At one hundred and twenty kilometres an hour that distance is about two hundred and six kilometres. Those two distances add up to the original four hundred and fifty kilometres, confirming the result. Thus the trains meet at about five forty‑three p.m.; the meeting point is roughly two hundred and forty‑four kilometres from Alpha City and about two hundred and six kilometres from Beta City. -------- 5. *** Analysis *** We need to answer: train leaves Alpha City at 3pm traveling toward Beta City at 90 km/h. Another leaves Beta City at 4pm traveling toward Alpha City at 120 km/h. Distance between cities 450 km. Straight route. Need meeting time and distances from each city. Must explain in plain English, step by step, no equations, no markdown, no bullet points, no asterisks, no LaTeX, no special formatting. So just plain text paragraphs. We must not use equations: but can describe calculations in words. We can still describe numbers. Provide reasoning. We need to compute when they meet: first train travels from 3pm, second from 4pm. So for first hour (3 to 4), only first train moves, covering 90 km (since speed 90 km/h). So after 4pm, distance remaining between them is 450 - 90 = 360 km. Then both trains travel towards each other. Their combined speed is 90 + 120 = 210 km/h. To cover 360 km at combined speed, time needed = distance / combined speed = 360 / 210 hours = 12/7 hours = about 1.7142857 hours = 1 hour and 0.7142857*60 minutes = 1 hour and about 42.857 minutes, roughly 1 hour 43 minutes. So from 4pm they need about 1 hour 43 minutes to meet. So meeting time = 4pm + 1 hour 43 minutes ≈ 5:43 pm (actually 5:42.9). So around 5:43 pm. Now distances from each city at meeting: The first train traveled from 3pm to meeting time: first hour (3-4) 90 km, plus additional 1 hour 43 minutes traveling at 90 km/h. In that extra time, distance traveled = 90 km/h * 1.7142857 h = about 154.2857 km. Add the initial 90 km gives total distance from Alpha City = about 244.2857 km. So about 244 km from Alpha City. Similarly, second train traveled from 4pm to meeting time: 1 hour 43 minutes at 120 km/h, distance = 120 * 1.7142857 = about 205.7143 km. So from Beta City it's about 206 km. Check sum: 244.3 + 205.7 = 450 km (makes sense). So meeting point is roughly 244 km from Alpha City and 206 km from Beta City. But we must not use equations. So we must describe steps: first hour only first train moves, covering 90 km. Then remaining distance is 360 km. Both trains approach each other, combined speed 210 km/h. At that speed, they would cover 210 km in one hour, leaving 150 km. Then after half an hour they would cover half of 210 = 105 km, leaving 45 km. Then after a quarter hour (15 minutes) they'd cover 52.5 km, which is more than remaining 45 km, so they meet before that. Actually we can compute more precisely: after one hour they still have 150 km left. After half hour they cover 105 km, leaving 45 km. At that point they have already traveled 1.5 hours total (since start of simultaneous travel). They still need to cover 45 km at combined speed 210 km/h. How long does that take? Since 210 km in an hour, 45 km is 45/210 hour = 0.2142857 hour = about 12.86 minutes. So total simultaneous travel time = 1 hour + 30 minutes + about 12.86 minutes = 1 hour 42.86 minutes. So meeting at about 5:42.86 pm. Good. But we cannot use equations, but we can explain as fractions. Use simple arithmetic. We can also compute distances from each city: first train traveled the initial hour 90 km, then in the next 1 hour it travels 90 km, in the next 42.86 minutes travels 90 * 0.7142857 = about 64.2857 km? Wait 90*0.7142857 = 64.2857. Actually earlier we computed total first train distance as 244.2857 km. Let's compute stepwise: after first hour: 90 km. Then during simultaneous travel: in the first hour of simultaneous travel they travel another 90 km, reaching 180 km from Alpha. Then in the remaining 42.86 minutes (0.7143 hour), they travel 90 * 0.7143 = about 64.2857 km, making total about 244.2857 km. So distance from Alpha City ~244 km. Distance from Beta City = total distance 450 - 244 = 206 km. But we must avoid equations; just describe. We should also confirm meeting time: 5:43 pm approx. Provide answer: around 5:43 pm, about 244 km from Alpha City, about 206 km from Beta City. We need to explain reasoning clearly and simply, step by step. No bullet points, no asterisks, no LaTeX, no Markdown. So just paragraphs. Let's craft final answer. *** Message *** The first train leaves Alpha City at three o’clock and travels at ninety kilometres each hour. In the first hour, from three until four, it is the only train moving, so it covers ninety kilometres. When the second train starts from Beta City at four o’clock, the two cities are still four‑hundred‑fifty kilometres apart, but ninety kilometres of that gap have already been closed by the first train. Therefore, after four o’clock there are three hundred and sixty kilometres left between the two trains. From four o’clock onward both trains travel toward each other. The first train continues at ninety kilometres an hour and the second train comes in at one hundred and twenty kilometres an hour. Together they close the distance at a rate of two hundred and ten kilometres each hour (ninety plus one hundred and twenty). Think of the remaining three hundred and sixty kilometres being reduced by that combined speed. In one hour they would together cover two hundred and ten kilometres, leaving a further one hundred and fifty kilometres still to go. In the next half‑hour they would close another one hundred and five kilometres, so after one hour and a half of simultaneous travel there would be only forty‑five kilometres left between them. To eliminate those last forty‑five kilometres at the same combined rate of two hundred and ten kilometres per hour takes a little more than a tenth of an hour. Since two hundred and ten kilometres are covered in sixty minutes, each kilometre takes about twenty‑nine seconds. Forty‑five kilometres therefore require roughly twelve minutes and fifty‑five seconds. Add that time to the one hour and a half of simultaneous travel: the two trains meet after about one hour, forty‑two minutes and fifty‑five seconds of traveling together. Because this joint travel started at four o’clock, the meeting occurs at about five o’clock, forty‑three minutes in the afternoon. Now find how far each train has travelled. The first train moved ninety kilometres in its solo hour, then another ninety kilometres in the first hour of the joint travel, and finally about sixty‑four kilometres in the remaining forty‑three minutes. Altogether it has gone roughly two hundred and forty‑four kilometres from Alpha City. The second train started only at four o’clock, so it has travelled for the same one hour, forty‑three minutes. At one hundred and twenty kilometres an hour, that amounts to about two hundred and six kilometres from Beta City. Thus the trains meet at approximately 5:43 PM, about 244 kilometres from Alpha City and about 206 kilometres from Beta City.